C/C++ 实现取得当前时间
C/C++ 实现取得当前时间
- #include<stdio.h>
- #include<time.h>
- #include<errno.h>
- #include<string.h>
- #include<unistd.h>
- #define N 10
- int main(int argc,char *argv[])
- {
- FILE *fp;
- int line=0;
- char buf[N];
- if((fp=fopen(“test.txt”,”a”))==NULL)
- {
- fprintf(stderr,”fopen failed:%s\n”,strerror(errno));
- return (-1);
- }
- while(fgets(buf,N,fp)!=NULL)
- {
- if(strlen(buf)<N-1||buf[N-2]==’\n’)
- line++;
- }
- while(1)
- {
- time_t t;
- time( &t);
- struct tm *t1;
- t1=localtime(&t);
- sprintf(buf,”%d %d/ %d/ %d %d:%d:%d\n”,++line ,t1->tm_year+1900,
- t1->tm_mon+1,
- t1->tm_mday,
- t1->tm_hour,
- t1->tm_min,
- t1->tm_sec),
- printf(“%s”,buf);
- fputs(buf,fp);
- fflush(fp);
- sleep(1);
- }
- fclose(fp);
- return 0;
- }
示例效果：
